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? asked in Science & MathematicsPhysics · 8 years ago

physics force, kinetics, and conservation problem?

please help. i just had this on my final exam and i wanted to check my answer. part a, i got SQRT(5) and part b: 1 meter

an exploding toy block of mass 3 kg from the right end of a table with friction coefficient mum = .5. the block explodes into two pieces-a 2 kg piece that slides 1 meter to the left and stops and the other that slides to the right, off the table.

a)what velocity does the smaller piece have as it leaves the table?

b)if the table is 1 meter tall, what horizontal distance (x) does the block travel before hitting the ground?

2 Answers

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  • 8 years ago
    Favorite Answer

    Work done on the heavy piece = F*d = µmgd = 0.5 * 2kg * 9.8m/s² * 1m = 9.8 J

    Therefore its initial KE = 9.8 J = ½mv² = ½ * 2kg * v² → v = 3.13 m/s

    Conservation of momentum tells us, then, that the smaller piece had velocity u = 6.16 m/s.

    How long did it take to drop?

    s = 1m = ½at² = ½ * 9.8m/s² * t² → t = 0.45 s

    Then its horizontal displacement was x = ut = 2.83 m

    I suspect that if you'd looked at the units attached to your √5 you'd have known that it must have been wrong. I hope you did better on the other problems.

  • ?
    Lv 4
    5 years ago

    the first issue you want to do is write out all the energies in touch contained in the project; the kinetic ability of the bullet, the kinetic ability of the bullet/container mixture, and maximum significantly, the flexibility of the friction rigidity. Its major to understand what's happening conceptually. A bullet is transferring with a particular kinetic ability and at the same time as it impacts the block, all of its kinetic ability is transferred. This consequences contained in the block having a sparkling kinetic ability (this skill a sparkling speed. I made that mistake). Now, if it weren't for the friction rigidity the block ought to flow always and the project should be no longer a chance without understanding the block's speed. So, decrease back to the mathematics... Set the )kinetic ability of the bullet) = (kinetic ability of the bullet/container mixture) - (ability of the friction rigidity). when you've finished this, you should ascertain for the speed of the bullet/container mixture. do this through placing the right hand area of this equation equation to 0 and fixing for v. Now that you've that the in common words issue left to unravel for is the speed of the bullet. do this through placing the perfect kinetic ability equivalent to the initial kinetic ability and fixing the v of the bullet. through how, I were given 12.86m/s yet i ought to have made a calculator blunders. i'm extraordinarily particular the tactic is reliable. Physics is exciting.

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