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Algebra 2 homework help!!!!?

write an equation in slope-intercept form (y = mx + b) for the line that has the given slope (m) and contains the given point

m= -1/2, (8,1)?

A. y= -1/2x+5

B. y= -1/2x+4

C. y= -1/2x+8 1/2

D. y= -1/2x+ -5

E. y= -1/2x-8 1/2

Determine the equation for the following information: m = 0, (–7, 8).

a.) y = –7

b.) y = 7

c.) y = 8

d.) y = –8

e.) y = 7x + 8

m= -2/3, (6,-5)

A. y= -2/3x+4

B. y= -2/3x-1

C. y= -2/3x+6

D. y= -2/3x-8/3

E. y=-2/3x+8/3

write an equation in slope-intercept form for the line containing the indicated points

Points: (1, –3) and (3, –5)

a.) y = x + 2

b.) y = –x + 2

c.) y = –x + 3

d.) y = –x – 2

e.) y = –x – 5

Points: (8, –3) and (–8, 3)

A. y= -3/8x+3

B. y= -8/3x-3

C. y= -8/3x+8

D. y= -3/8x+8

E. y= -3/8x

Points: (–6, –6) and (–3, 1)

A. y= 7/3x-8

B. y= 3/7x+8

C. y= 7/3x+8

D. y= 3/7x-6

E. y= 7/3x+1

write an equation, in slope-intercept form for the line that contains the given point and is parallel to the given equation. y= -2/3x-7 --> y= (-2/3)x-7

(–2, 3); y = –3x + 2

(4, –3); –4x + y = 7

(3, 0); –x + 2y = 17

(–6, 2); y = (–2/3)x – 3

write an equation, in slope-intercept form, for the line that contains the given point and is PERPENDICULAR

(–2, 5); y = –2x + 4

(3, –1); 12x + 4y = 8

(–2, 4); x – 6y = 15

(2, 5); 6x + 2y = 24

Describe the relationship of the slopes of the equations of two parallel lines. Include an example.

Describe the relationship of the slopes of the equations of two perpendicular lines. Include an example.

Explain how to write an equation for the line that contains the point (2, –3) and is parallel to the graph of x + 2y = 2.

Explain how to write an equation for the line that contains the point (2, –3) and is perpendicular to the graph of x + 2y = 2.

find the slope of each line containing

Points: (3, 4) and (5, 4)

Points: (–2, 8) and (–2, –1)

What is the slope of the line that contains the given points?

(1/2 , -3) and (3 , -1/2)

Points: (–4, 8) and (–3, –6)

Update:

there are 150 questions on this homework asignment so im not asking you to do everythign for me. i need help and if all your going to say it "do it yourself", or anything like that dont bother commenting. i will report you and block you. thanks. :) thank you for your help!

Update 2:

this is not a test its a homework assignment and im not cheating im asking for help so like i said im gonig to report and block anyone who sais anything about that. if your not going to help me than dont even comment. thank you:)

4 Answers

Relevance
  • 8 years ago
    Favorite Answer

    Using the formula:

    y-y1= m(x-x1)

    the '1''s are subscript.

    m= -1/2 x1=8 , y1= 1

    y-1= -1/2( x-8)

    y-1 = -1/2x +4

    y = -1/2x +4 +1

    y = -1/2x +5

    So your answer is A

    2. m = 0, (–7, 8).

    using the same formula as in question '1'

    y- 8 = 0(x+7)

    y-8=0

    y= 8

    choose option 'c'.

    3. m= -2/3, (6,-5)

    y -(-5) = -2/3 ( x-6)

    y+5 = -2/3x +4

    y = -2/3x +4-5

    y= -2/3x -1

    The answer is option B.

    4.

    Points: (1, –3) and (3, –5)

    x1= 1, y1 = -3 x2=3, y2=-5

    first, we need to find 'm'

    use m= y2-y1/x2-x1

    = -5 - (-3)/ 3 -1

    = -2/2

    = -1

    M= -1 and use one of the two set of coordinates (1,-3)

    y-y1=m(x-x1)

    y - (-3) =-1(x-1)

    y +3 = -x +1

    Y= -x +1-3

    y = -x-2

    5. Points: (8, –3) and (–8, 3)

    m = y2-y1/x2-x1 = 3-(-3)/-8-8

    = 6/-16

    = -3/8

    m= -3/8 (8, -3)

    y-y1=m(x-x1)

    y +3= -3/8(x-8)

    y+3 = -3/8x+3

    y = -3/8 x

    6.

    Points: (–6, –6) and (–3, 1)

    m = y2-y1/x2-x1 = 1 +6/-3+6

    = 7/3

    m=7/3 (-3,1)

    y-1= 7/3(x+3)

    y-1 = 7/3x +7

    y = 7/3x +8

    parallel lines have the same gradient.

    for example y= 2x+3 and y=2x-4 are parallel lines as they both have a gradient of '2'

    As for perpendicular lines , the product of their gradients will always equal to -1.

    for example y= 2x+3 and y =-1/2x-1 are perpendicular, they cross at right angles and the product of their gradients is -1.

    point (2, –3) and is parallel to the graph of x + 2y = 2.

    it has a gradients of 1. parallel lines share the same gradient:

    so m= 1 (2,-3)

    y-y1= m(x-x1)

    y+3= (x-2)

    y= x-2-3

    y=x-5

    (2, –3) and is perpendicular to the graph of x + 2y = 2.

    so to find the gradient we will take the negative reciprocal of the above line's gradient

    m= -1/1=-1 (2,-3)

    y-y1= m(x-x1)

    y+3 = -(x-2)

    y+3= -x +2

    y = -x +2-3

    y = -x-1

    find the slope of each line containing

    Points: (3, 4) and (5, 4)

    by slope we mean gradient or 'm'

    m= y2-y1/x2-x1

    = 0/2=0

    Points: (–2, 8) and (–2, –1)

    m= -1-8/-2+2= -9/0= infinity/undefined

    What is the slope of the line that contains the given points?

    (1/2 , -3) and (3 , -1/2)

    m= -1/2+3/3-1/2

    = 5/2/5/2

    = 1

    Points: (–4, 8) and (–3, –6)

    m= -6-8/-3+4

    = -14/1= -14

  • 8 years ago

    Slope is Rise over Run. So for example 1/2 would mean that you start at a point and count UP 1 space and RIGHT 2 spaces. For something like -3/4, you would start at a point and count DOWN three spaces and RIGHT 4 spaces. If the slope is a whole number assume that there is a 1 below it eg. 4 would actually be 4/1. (The denominator always goes rightward.) The y-intercept (Also known as b) is where the line crosses the y axis. (That is the center line going up and down on a graph.)

    When you are given coordinates, they go (x,y). So in (-7,8), the -7 is x, and the 8 is y. so the equation would be.

    y= -7x + 8

    To find the line you would go to a graph, and since -7x is the slope, and it is a whole number, you would assume that there is a 1 under the -7. So it would be -7/1. You would find any random point on the graph, and count DOWN 7 spaces, and to the RIGHT 1 space. Then you adjust that line to cross the center line (y- axis) where b is, which in this case is 8.

    (x,y) x is the slope, and y is the y-intercept or "b."

    Perpendicular lines have opposite slopes. (eg. 1/3x + 2 and -1/3x + 2)

    Parallel lines have the exact same slope, but different y intercepts or b. (eg. 1/4x + 2 and 1/4x - 25)

    It may seem long and complicated, but it's not.

  • 8 years ago

    use the formula (y-y1)= m(x-x1)

    here m= -1/2 and x1=8 and y1 =1

    y-1 =-1/2(x-8)

    y-1 = -1/2 x +4

    y = -1/2 x +5 ........................Ans

  • Como
    Lv 7
    8 years ago

    Sorry---too many questions.

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