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At a construction site a pallet of bricks is to be suspended by attaching a rope to it and connecting the othe?
At a construction site a pallet of bricks is to be suspended by attaching a rope to it and connecting the other end to a couple of heavy crates on the roof of a building. The rope pulls horizontally on the lower crate, and the coefficient of satic friction between the lower crate an the roof is 0.666. The crates on the roof weigh 150lbs and it is on top of a 250 lb crate.
What is the weight of the heaviest pallet of bricks that can be supported this way, and what is the friction forse on the upper crate under these conditions.
STEP BY STEP PLEASE
2 Answers
- WoodsmanLv 78 years agoFavorite Answer
It sounds like the crates are stacked, the bottom weighing 250 lb, the other 150 lb. Then the normal force under the bottom crate is Fn = 400 lb, making the friction force
Ff = µFn = 0.666 * 400lb = 266.4 lb.
Therefore this is the heaviest pallet of bricks that can be supported in this way.
I'm not sure I understant the last question, as far as "under these conditions" goes. As long as the pallet of bricks is in equilibrium, the friction force on the upper crate is zero.
- Anonymous5 years ago
Would that happen to be Donkey Kong? I'd fetch Mario, Luigi and Link to help me defeat him!
