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? asked in Science & MathematicsMathematics · 8 years ago

I need help with Algebra 2?

Describe how an equation of a line in slope-intercept form with a steep slope might be different from the equation of a line with a less steep slope. Give an example of each.

2 Answers

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  • 8 years ago
    Favorite Answer

    Slope is rise over run, so if m in your equation, y=mx+b is larger than one in a different equation, the m that is larger will be the larger slope.

    By recognizing what slope is in a simple way (rise over run) you can see that a m of 5 would require a rise of 5 and a run of 1 because of m=5/1 and a slope of 2 would require a rise of 2 and a run of 1 because of m=2/1. Since the rise is greater in m=5 than m=2 before the run, the slope of m=5 is much steeper.

    Essentially: the slope of line f(x)=5x is going to be steeper than the slope of the line of g(x)=2x.

    :)

  • Bob B
    Lv 7
    8 years ago

    A line with a steep slope has a higher coefficient for the x term than a more shallow line does.

    Examples:

    y = 12x + 2 (Steep - This line rises by 12 units of y for each 1-unit increase in x.)

    y = 2x + 2 (More shallow - This line only rises by 2 units of y for each 1-unit increase in x.)

    y = (1/4)x + 2 (Even more shallow - This line rises by only 1 unit of y for every 4-unit increase in x.)

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