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Need some help, please~?
Suppose that a certain municipality uses the equation y=3(x-50)+30 to determine the fine assessed a car which exceeds the 50 mph speed limit. Let x=speed of the car (in mph) and y=corresponding fine in dollars.
a)What is the fine for traveling at 55 mph?
b)If the fine is $126, what is the speed of the car?
c)If car A travels at 60 mph and car B travels at 90 mph, then car B is traveling 50% faster than car A. However the fine for car B is what percent higher than that of car A?
1 Answer
- icemanLv 78 years agoFavorite Answer
y = 3(55 - 50) + 30
y = 15 + 30 = $45
3x - 150 + 30 = 126
3x = 246
x = 82 mph
Edit: and for C:
y(A) = $60
y(B) = $150
(150 - 60)/60 = 150% higher