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STOICHIOMETRY QUESTION?!????!!?!?! 10 POINTS!?
You need to produce 100.0 g of FeCl3 in the following reaction. If the percent yield of the reaction was 85.0%, how many grams of iron would you need to start with?
The equation for the reaction is: 2Fe + 6HCl -----> 3H2 + 2FeCl3
1 Answer
- Anonymous8 years agoFavorite Answer
Iron and FeCl3 have same no. of moles in the reaction..
So, 1 mole of Iron gives 1 mole of FeCl3...
Now,
1 mole of FeCl3 = 274.5 g ( 56*1 + 35.5*3 )
So, 100 g of FeCl3 = 100/274.5 moles i.e. 0.364 moles...
0.364 is also the no. of moles of Fe
But it is the 85 % of the original..
So, original Fe = 0.364*100/85= 0.428 moles
Then we have , 56 gm = 1mole
0.428 moles of Fe = 56*0.428 g = 23.968 g ( approx)
So, we need 23.968 g ( approx) to yield 100 g FeCl3.
Source(s): personal