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STOICHIOMETRY QUESTION!!!!!!!!!!! 10 POINTS!?
What volume of 0.50M* AgNO3 is required to react with 25.0 liters of 1.5M CaCl2?
*M stands for Molarity, which is moles/liters
The equation for the reaction is: 2AgNO3 + CaCl2 ---> 2AgCl + Ca(NO3)2
1 Answer
- Lexi RLv 78 years agoFavorite Answer
moles CaCl2 = molarity x litres
= 1.5 M x 25.0 L
= 37.5 moles
the balanced equation tells you that 1 mole CaCl2 reacts with 2 moles AgNO3
So moles AgNO3 needed = 2 x moles CaCl2
= 75.0 mol
Now work out what volume of the AgNO3 solution has this many moles
molarity = moles / Litres
Therefore litres = moles / molarity
= 75.0 mol / 0.50 M
= 150 L (2 sig figs)
