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CHEMISTRY QUESTION!??!??!!???!?
What volume of 0.50M* AgNO3 is required to react with 25.0 liters of 1.5M CaCl2?
*M stands for Molarity, which is moles/liters
The equation for the reaction is: 2AgNO3 + CaCl2 ---> 2AgCl + Ca(NO3)2
2 Answers
- 8 years agoFavorite Answer
Remember that you need to get the numbers in MOLES to compare. M = mol/L.
1.5 mol/L CaCl2 * 0.0250 L = 0.0375 mol CaCl2
According to the reaction equation, 1 mol of CaCl2 reacts with 2 moles of AgNO3.
0.0375 mol CaCl2 * 2 = 0.0750 mol AgNO3.
0.50 mol/L AgNO3 = 0.0750 mol AgNO3 / x L
x = 0.15 L or 150 mL
Remember to check sigfigs. You need 2 sigfigs and (yay!) the answer is already in 2 sigfigs so you're done :)
