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Why is diboron tetrachloride planar as a solid but staggered as a gas?
1 Answer
- TimothyLv 68 years agoFavorite Answer
B₂Cl₄ has a B–B single bond, as expected based on the Lewis diagram for the molecule. The linked figure below shows the structure in the solid state; the B–B distance, 1.752 Å, is just what one expects for a B–B single bond. The B–Cl distances average 1.726 Å. The solid state structure shows that there are some long intermolecular B–Cl contacts roughly above and below the B₂Cl₄ plane at an average distance of 3.26 Å. (These are shown as light dotted lines.) Since the boron atoms have empty p orbitals directed into that region and the Cl atoms on neighboring molecules have lone pairs of electrons, these interactions are reasonably characterized as Lewis acid-base interactions that are more easily achieved if chloride lone-pair–lone-pair repulsions are avoided and that favors a planar B₂Cl₄ structure. In the gas phase, there are no such intermolecular contacts and Cl–Cl steric repulsions in the planar structure (3.46 Å) are eliminated of the molecule adopts a staggered structure.
Source(s): From, Atoji, M., Wheatley, P.J., Lipscomb, W.N., JCP, 1957: http://i713.photobucket.com/albums/ww133/Sane_Pers...