CAN SOMEBODY PLEASE SOLVE THIS I REALLY REALLY NEED HELP?

Try googling "system of equations"

Solve this system by elimination.

8x + 5y = 22.

6x + 2y = 13.

Multiply the first equation by 3, giving

24x + 15y = 66.

Multiply the second equation by 4, giving

24x + 8y = 52.

Subtract the new #2 from the new #1:

24x + 15y = 66

-(24x + 8y = 52)

-----------------------

0x + 7y = 14, or

7y = 14, or

y = 2.

Put this into one of the original equations, to solve for x:

6x + 2(2) = 13, or

6x + 4 = 13, or

6x = 9, or

x = 9/6 = 3/2. The solution point is (3/2,2).

check:

8(3/2) + 5(2) = 24/2 + 10 = 12 + 10 = 22 ... yes.

6(3/2) + 2(2) = 18/2 + 4 = 9 + 4 = 13 ... yes.

= = = = = = = = = = = = = = =

Solve this system by substitution.

2x - 3y = 12.

x - 4y = 6.

Rearrange one of the equations so as to put one variable in terms of the other. It will be easier with #2.

Since x - 4y = 6, add 4y to both sides to get

x = 4y + 6.

Now this can be used in place of x in the first equation, to solve for y:

2(4y + 6) - 3y = 12, or

8y + 12 - 3y = 12, or

5y + 12 = 12, or

5y = 0, so

y = 0.

Put this into one of the original equations:

x - 4(0) = 6, or

x - 0 = 6, or

x = 6. The solution point is (6,0).

check:

2(6) - 3(0) = 12 - 0 = 12 ... yes.

6 - 4(0) = 6 - 0 = 6 ... yes.

8x+5y=22

6x+2y=13

multiply first equation with 2 and second equation with 5

2(8x+5y)=2*22

5(6x+2y)=5*13

16x+10y=44

30x+10y=65

multiply first equation with -

-16x-10y=-44

30x+10y=65

add two equations

14x=21

x=21/14=3/2

x= 3/2

y=2

2)

2x-3y=12

x-4y=6

2x-3y=12

x=6+4y

substitute x in equation 1

2(6+4y)-3y=`12

12+8y-3y=12

5y=0

y=0

x=6