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? asked in Science & MathematicsMathematics · 8 years ago

Difficult math problem?

My teacher has a extra credit puzzle that's worth a large sum of points. So the puzzle involves a 5X5 square with 25 slots. Each slo has seemingly random numbers inside, So 5 slots need to be chosen and each slot needs to be in a different row and column of the other selected slots, kind of like sodoku. Somehow if all 5 of these random slots are selected, the numbers inside them will always equal a number when all of them are added. Can anyone tell me the solution to this puzzle, and how you come up with the numbers to equal the designated answer? 10 pts for the most simplified straight forward answer

2 Answers

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  • M3
    Lv 7
    8 years ago
    Favorite Answer

    i think you mean a magic square like the one below, which adds up to 65 for each row, column and the 2 main diagonals

    17 24 01 08 15

    23 05 07 14 16

    04 06 13 20 22

    10 12 19 21 03

    11 18 25 02 09

    the rules for constructing it by de la Loubere's Algorithm can be seen at

    http://www.jcu.edu/math/vignettes/magicsquares.htm

  • 4 years ago

    problem a million ? i^2 = (a million/3) n^3 + (a million/2) n^2 + (a million/6) n hence a hundred ? i^2 = a hundred [ (a million/3) (59)^3 + (a million/2) (59)^2 + (a million/6) (59) ] problem 2 ? i^3 = (a million/4) n^4 + (a million/2) n^3 + (a million/4) n^2 hence = 10 ? i^2 (i-40 9) = 10 ? i^3 - 490 ? i^2 = 10 [ (a million/4) (a hundred)^4 + (a million/2) (a hundred)^3 + (a million/4) (a hundred)^2 ] - 10 [ (a million/4) (59)^4 + (a million/2) (59)^3 + (a million/4) (59)^2 ] - 490 [ (a million/3) (a hundred)^3 + (a million/2) (a hundred)^2 + (a million/6) (a hundred) ] + 490 [ (a million/3) (59)^3 + (a million/2) (59)^2 + (a million/6) (59) ]

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