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chemical kinetics question. please help!?
1. Calculate for the initial concentrations of Na2S2O3 and HCl for each run, knowing the original concentrations and volumes: 0.15M Na2S2O3, 3M HCl.
Run 1 - 20ml Na2S2O3, 6ml distilled water, 4ml HCl
Run 2 - 10ml Na2S2O3, 16ml distilled water, 4ml HCl
Run 3 - 5ml Na2S2O3, 21ml distilled water, 4ml HCl
Run 4 - 10ml Na2S2O3, 2ml distilled water, 3ml HCl
Run 5 - 10ml Na2S2O3, 3ml distilled water, 2ml HCl
Run 5 - 10ml Na2S2O3, 4ml distilled water, 1ml HCl
1 Answer
- Chris SLv 68 years agoFavorite Answer
.............................0.15M.................
............TOTAL...Na2S2O3.............
............VOL.......DILUTION.............
Run 1-30ml......0.15x20/30=0.10M
Run 2-30ml......0.15x10/30=0.050
Run 3-30ml......0.15x 5/30=0.025M
Run 4-15ml......0.15x10/15=0.10M
Run 5-15ml......0.15x10/15=0.10M
Run 6-15ml......0.15x10/15=0.10M
.............................3M
............TOTAL......HCl
............VOL..........DILUTION
Run 1-30ml........3x4/30=0.4M
Run 2-30ml........3x4/30=0.4M
Run 3-30ml........3x4/30=0.4M
Run 4-15ml........3x3/15=0.6M
Run 5-15ml........3x2/15=0.4M
Run 6-15ml........3x1/15=0.2M