1D Kinematics: Meeting Problem?

Use s = ut + ½at²

s(A) is the distance traveled by A

s(B) is the distance traveled by B

When they pass:

s(A) = s(B)

u(A)t + ½a(A)t² = u(B)t + ½a(B)t²

(½a(A) - ½a(B))t² + (u(A) - u(B))t = 0

Factorise:

t {(½a(A) - ½a(B))t + (u(A) - u(B))} = 0

Hence either t = 0, or

(½a(A) - ½a(B))t + (u(A) - u(B)) = 0

t = - (u(A) - u(B)) / (½a(A) - ½a(B)) = -(8.4 - 3.6) / ½(3.5 - 5.9) = 4.8 / 1.2

t = 4 seconds (ANSWER)

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