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a Question about H NMR?

A singlet at 7-8 ppm would b what structure. Would it be an aromatic compound. There is also a doublet at 3.5ppm if that helps at all.

2 Answers

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  • ?
    Lv 7
    8 years ago
    Favorite Answer

    As the other answerer noted, that would be an aromatic proton. However, a multiplicity of one (singlet, one peak) would mean that the proton does not have any near neighbors on the ring. For example (dots used as placeholders only):

    ........X..H

    ........|....|

    .......C=C

    ....../......\

    H-C.......C-Y

    ......\\......//

    ........C-C

    .........|...|

    ........Z..H

    The ring protons would appear as singlets if all three substituents (X, Y, Z) were the same.

  • Anonymous
    8 years ago

    7-8 usually implies aromatic, while the doublet would refer to another group on the molecule, perhaps a methylated substituent

    For more information on how to do these problems, perhaps check out these youtube videos

    http://leah4sci.com/ms-nmr-ir-spectroscopy/

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