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There is a math problem that I'm tots confused on and i have two different sets of equations?
Let f be a function such that f"(x)=6x+8. Find F(x) if the graph of is tangent to the line y=3x-2
What I did was integrated f(x) to x^3+4x^2+Cx+D t
y+3x-2 the derivative is three so i set 3 equal to f(x) and found D is 3 so i guess my problem is how to find C
3 Answers
- RenieLv 68 years agoFavorite Answer
There is not enough information. Did they give you the point of tangency or any other point?
If the derivative is 3, that will not tell you that D is 3. It will only tell you that f ' = 3 at the point of tangency. This is also a point on the function.
I hope this helps!
- Anonymous8 years ago
http://www.webmath.com/index.html
Check this site out. Find your category (algebra, trig, etc.) Then select the kind of problem it is (percentages, fractions, etc.) Then put in the equation. Click solve. Voila!
Source(s): http://www.webmath.com/index.html - Anonymous8 years ago
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