time of our solar system?

If you are looking at anything from a distance you must take into account the time difference for the observation to reach you on Earth. If we want to compute distance or large distances in space-time, we must add an additional parameter to the normal x, y, z used to compute distance that are close.

For observations that are here (on Earth), distance is a function of x, y, and z {d(x, y, z)} is:

d(x, y, z) = √{x² + y² + z²}

For observations in space-time, distance is a function of x, y, z, and the time (Δt) that it takes light to traverse the spatial distance:

d(x, y, z, Δt) = √{x² + y² + z² - (CΔt)²}

NOTE: The time difference is multiplied by the velocity of light (C) so that it becomes a distance; otherwise, the units would be inconsistent.

You see what you see because the space-time distance of what you see has become zero for that observation.

Consider the case where an event occurs to an object 4.24 light-years away. Let's pretend that Alpha Centauri exploded at the exact moment that you are reading this. You see the explosion when the distance terms plus the time term equal zero; 4.24 years from now. Until that time, the event is in imaginary space-time on its way to you. For the next 4 years, you could look at Alpha Centauri with a telescope and you would see nothing out of the ordinary but 4.24 years from now -- BOOM!

You are speaking of 2 different things.-

Time --- is the measure of how long an event takes.

Speed --- is the measure of how fast an object is moving with respect to some other object.

Thus a planet (our earth) may take 1 year to orbit the sun. And as such, we can compute the earth's speed with respect to the sun. The orbit of the earth is almost a circle so it is Pi * diam

= pi * 150,000,000 km

Earth travels that far in one year = 365 * 24 hours

D= R*T

Rate = D/T

= pi * 150,000,000/365 * 24 km/hour

= 53,816 km /hour

Meteors are orbiting the sun and they move at about the same speed when they strike the earth's atmosphere.