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? asked in Science & MathematicsMathematics Β· 8 years ago

How would you solve this algebraically?

2x^2-5x=x^2+1

I moved it all to one side like so:

2x^2-5x-x^2-1=0

But after trying factoring, completing the square, everything, I keep ending up with crazy numbers and fractions that I know can't work out.

2 Answers

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  • Fazaldin A
    Lv 7
    8 years ago
    Favorite Answer

    2x^2-5x=x^2+1

    I moved it all to one side like so:

    2x^2-5x-x^2-1 = 0,

    OR,

    x^2 -5x -1 = 0,

    OR,

    x = [5 +/- sqrt(5^2 + 4*1)] / 2

    x = [5 +/- √29] / 2 = (5 +/- 5.39) / 2,

    THus,

    x = 5.195, & x = -0.195 >==========================< ANSWER

  • Stephanie
    8 years ago

    I don't know if it's right because I have been out of pre-algebra for a LONG time, but I got x= -4x squared. -Stephanie<3

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