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How do you solve for x in this: 12x=32+x^2?
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- Ceiling CatLv 68 years agoFavorite Answer
Make your equation equal to zero by subtracting 12x from both sides.
0 = x^2 - 12x + 32
Then factorize. You need two numbers that multiply to give 32 and add to give -12. Eight and four will work.
0 = (x - 4)(x - 8)
x has two solutions, x = 4 and x = 8
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