Can you halep me solve these problems?

1: For the first problem you need to solve for x. You should first multiply the expressions and set it equal to zero.

x^2-4x - 5 = 16 <-- Multiply

x^2 -4x-20 = 0 <-- Add 16 to both sides

Since this is not factorable, you should use the quadratic formula to solve for x.

2:

(21ax - 35bx) + (-10by + 6ay) <-- Split the expression in half like this. This only works if you have four terms.

7x(3a - 5b) + 2y(-5b + 3a) <-- Factor each of the two pairs by taking out a common multiple.

7x(3a - 5b) + 2y(3a - 5b) <-- switch 3a and -5b to make it easier to understand. Notice that the two numbers in the parenthesis are the same.

(7x + 2y)(3a - 5b) <-- Multiply the numbers outside of the parenthesis by the numbers inside of the parenthesis, this will only work if the numbers inside of the parenthesis are the same in both pairs. This is the final solution. You can check your answer by multiplying both expressions, you should get your initial value, which is 21ax - 35bx - 10by + 6ay.

3:

(10x^2 + 25x) + (4xy + 10y) <-- Split the expression in two, like this. Only do this if you have four groups of numbers.

5x(2x + 5) + 2y(2x + 5) <-- Factor out a common multiple from both groups. The two expressions that remain the the parenthesis should be the same, in this case they are both "2x + 5".

(5x + 2y)(2x + 5) <-- Multiply the numbers outside of the parenthesis by the numbers inside of the parenthesis.

4:

4x^2 - 1 = 0

(2x + 1)(2x - 1) = 0 <-- When you do not have a middle term, meaning when you only have and X^2 and an X^0, and when both of them have perfect square roots, sqrt(4) = 2 sqrt(1) = 1, and when the last term is a negative number, you can factor the expression like this.

x = -1/2 or x = 1/2 <-- To solve for zero choose each expression and set them to zero. If one is zero, both are zero.

5:

2x^2 + 4x - 5

-10 <-- If you multiply -5 and 2 you will get -10. What factors of -10 add up to get 4? The answer is none. This means that it can't be factored.

6:

x(p + 1) - (p + 1) <-- It doesn't seem like there is anything to do here, it's already factored.

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Let me pour some reasoning on you...

If m times n = 0

then isn't m = 0 and n = 0 ?

am I lying? no I'm not :)

With that in mind, do your necessary equating

10x^3-25x^2+2x-5? and check