indefinite integral....................math?

find ∫ (x5 + 1) dx.

int(x^5 +1, x)

=x^6/6 +x +k where k is constant according to power rule of integral

∫ (x5 + 1) dx = ∫ (x5 dx + ∫ (1) dx = (1/6)x^6 + x

∫ (x^5 + 1) dx=∫ x^5dx+∫ 1dx=x^6/6+x+c

beacause ∫ x^ndx=x^(n+1)/n+1

∫ (x5 + 1) dx.= ∫x^5dx +1dx =[x^5+1]/[5+1]+x+c=x^6/6 +x+c

c is arbitrary constant

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