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Could someone help me with this?
b. Find the mean and standard deviation for the 65 closing prices in your sample and provide the printout below. Use these values as estimates of the mean and standard deviation found in the population of all closing prices. Suppose that the closing prices were normally distributed (regardless of what your plot indicated in part a). Find the proportion of all closing prices that would exceed $15 in the population. I want you to show your work. To receive full credit, you should include pictures of the normal curve (labeled with both x and z-values) with the pertinent probabilities shaded in the picture.
Mean = 43.314
Standard Deviation = 126.050
Need to use both the X and Z curve.
Thanks for the help!
1 Answer
- 8 years agoFavorite Answer
Using the information you provided you have the information for the curve using x values.
draw curve, 43.314 in the number associated with the line in the middle. On the left side of the curve draw line label 15 and shade curve from that line to the right.
Converting info to z scores.
(15 - 43.314)/126.050 = -.22
draw curve. 0 is the number in the middle. draw line on the left label that line -.22 shade to the right.
Probability of both will be the same using charts or normalcdf the probability is .5871
