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Pressure and Density (10 points)?
Consider a box with a lid 1.2 m wide and 0.82 m long. If the inside of the box is evacuated (i.e., its pressure is zero), how much force is required to open the lid?
The answer is 99400 N
Thank you.
2 Answers
- ReginaldLv 78 years agoFavorite Answer
We have to overcome atmospheric pressure, which varies with altitude, but at sea level
it is 101,325 pascals or 101.325 KPa. One pascal is defined as one newton per square
meter, so we need to find the area of the lid. If it's 1.2 meter wide and 0.82 meter long
its area is 1.2 times 0.82, or 0.984 sq. meter.
The atmospheric pressure at sea level is 101,325 newtons per sq. meter, and the area
of the lid is 0.984 sq. m. so the force holding it down is 101325 times 0.984, or
99703 newtons. That is slightly more than the answer you have, so perhaps the box
is at a location above sea level where the atmospheric pressure is 101,016 Pa.
Just multiply the atmospheric pressure in pascals by the lid area in sq. meters.
Source(s): college physics - aletrizLv 44 years ago
The water has rigidity consistent with how deep the water is. The deeper you push the try tube the extra suitable the rigidity. i believe water rigidity will strengthen via a million environment each 33 ft !