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Pressure and Density (10 points)?

Consider a box with a lid 1.2 m wide and 0.82 m long. If the inside of the box is evacuated (i.e., its pressure is zero), how much force is required to open the lid?

The answer is 99400 N

Thank you.

2 Answers

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  • 8 years ago
    Favorite Answer

    We have to overcome atmospheric pressure, which varies with altitude, but at sea level

    it is 101,325 pascals or 101.325 KPa. One pascal is defined as one newton per square

    meter, so we need to find the area of the lid. If it's 1.2 meter wide and 0.82 meter long

    its area is 1.2 times 0.82, or 0.984 sq. meter.

    The atmospheric pressure at sea level is 101,325 newtons per sq. meter, and the area

    of the lid is 0.984 sq. m. so the force holding it down is 101325 times 0.984, or

    99703 newtons. That is slightly more than the answer you have, so perhaps the box

    is at a location above sea level where the atmospheric pressure is 101,016 Pa.

    Just multiply the atmospheric pressure in pascals by the lid area in sq. meters.

    Source(s): college physics
  • 4 years ago

    The water has rigidity consistent with how deep the water is. The deeper you push the try tube the extra suitable the rigidity. i believe water rigidity will strengthen via a million environment each 33 ft !

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