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Archimedes' law- find height of something floating (10 points)?

A rectangular block of wood (density 725 kg/m^3) of height 26 cm floats in a lake. What is the height of the wood above the water level?

the answer is 7.15 cm

I need help getting there, thank you :)

2 Answers

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  • Anonymous
    8 years ago
    Favorite Answer

    There must be a equilibrium

    so, first you have to search what forces act on your block of wood; that is the earth's gravity, and the buoyant force by the water.

    so, lets write that down

    G=F_b

    G=density(of wood) * (total) Volume of wood* earth gravity

    F_b = density(of water) * Volume of the block in the water * earth gravity

    volume = Surface* height

    So what you get

    density_wood*total height*surface*gravity = density_water * height under water * surface* gravity

    As you can see, the value of the surface and gravity doesn't matter here

    answer: height under water = total height * (density_wood)/(density_water)

    = (26) * (715/1000)

    = 18.59 cm

    so the part above water is

    26-18.59=7.41 cm

    This is different from your answer, but i don't see a mistake in my solution ;)

    Source(s): Trust me, i'm an engineer :)
  • Anonymous
    5 years ago

    This question is difficult to understand for me too

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