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Archimedes' law- find height of something floating (10 points)?
A rectangular block of wood (density 725 kg/m^3) of height 26 cm floats in a lake. What is the height of the wood above the water level?
the answer is 7.15 cm
I need help getting there, thank you :)
2 Answers
- Anonymous8 years agoFavorite Answer
There must be a equilibrium
so, first you have to search what forces act on your block of wood; that is the earth's gravity, and the buoyant force by the water.
so, lets write that down
G=F_b
G=density(of wood) * (total) Volume of wood* earth gravity
F_b = density(of water) * Volume of the block in the water * earth gravity
volume = Surface* height
So what you get
density_wood*total height*surface*gravity = density_water * height under water * surface* gravity
As you can see, the value of the surface and gravity doesn't matter here
answer: height under water = total height * (density_wood)/(density_water)
= (26) * (715/1000)
= 18.59 cm
so the part above water is
26-18.59=7.41 cm
This is different from your answer, but i don't see a mistake in my solution ;)
Source(s): Trust me, i'm an engineer :) - Anonymous5 years ago
This question is difficult to understand for me too