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Archimedes' law- Completly immersed (10 points)?
Consider a wooden block of density 650 kg/m^3 and volume 2.2 m^3. What force is required to hold it completely under water?
The answer is 7550 N
Please help me get there. Thanks.
1 Answer
- electron1Lv 78 years agoFavorite Answer
The weight of the block is pulling it downward, and the buoyant force is pushing it upward.
Weight = mass * g, Mass = density * volume
Weight = 650 * 2.2 * 9.81 = 14,028.3 N
Buoyant force = Volume of displaced water * Density of water * g
Since the block is completely under water, the volume of displaced water is equal to the volume of the block.
Buoyant force = 2.2 * 1000 * 9.81 = 21,582 N
21,582 – 14,028.3 = 7,553.7 N
To 3 sig digs, F = 7550 N
