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May you please factor 16n^2+112n-120=0?
I've been stumped as I am trying to finish this word problem on this part.
factor 16n^2+112n-120=0
I need it to be in this format ( + )( - )=0
4 Answers
- SteffieLv 48 years agoFavorite Answer
2n(8n + 56) - 120=0
2n(8n + 56)=120
Divide both sides by 2
n(8n + 56)=60
8n^2 + 56n - 60 = 0
- 8 years ago
If you have difficulties with factorization, use the quadratic formula;
x=(-b屉(b^2-4ac))/2a
In the eqn. 16n^2+112n-120=0
a=16 , b=112 and c=-120
n=(-112屉(112^2-4(16)(-120)))/2(16)
n= (-112屉4864)/32
n=(-112 + 69.7)/32 or n=(-112 - 69.7)/32
n=-1.32 or n=-5.68
- 8 years ago
it's impossible if you want a whole number.. the 112n part seems to be the problem...
