Algorithm or program in basic c language to print the reverse of a number...please help?

satish's answer is incorrect as it always outputs a 0 as the last digit instead off the first digit of the original number. For example, take 12345, the algorithm he/she has proposed will output 54320.

A quicker (shorter) approach would be to use the modulus.

1. We take the number's remainder when divided by 10 by using "remainder = number % 10" - without quotes.

2. We divide the original number by 10.

3. Print the remainder out.

4. If number is zero, then terminate, otherwise, go to step 1.

void printReverseOfNumber(int number)

{

    int remainder;

    while(number != 0)

    {

        remainder = number % 10;

        number /= 10;

        printf("%d", remainder);

    }

}

int main(int argc, char* argv[])

{

    printReverseOfNumber(12345); // outputs 54321

    return 0;

}

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let us say the number is 12345

first you divide the number with 10

you get 1234 now multipluy this with 10 '

you get 12340 subtract this from 12345 you get 5 which is the last number.

now repeat the same with

1234 this time divide with 10

123 multiply witn 10 1230

subtract

1234-1230 = 4

we do this till the quoitiet is 0

int printrev(int number)

{

int temp;

while(1)

{

int temp = (number/10)*10;

if (temp ==0)

{

printf("%d",temp);

break;

}

temp = number -temp;

printf("%d\t",temp);'

number = number/10;

}

}

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