How to use my TI - 83 to find standard deviation?

Use [2nd][Stat](List) > Math > 7:stdDev(.

In terms of key sequences:

[2nd][Stat] [(Left)] [7]

[2nd][ ( ] [5] [ , ] [1][5] [ , ] [2][0] [ , ] [1][0] [ , ] [1][0]

[Enter]

(stat) (enter) (5) (enter) (1) (5) (enter) (2) (0) (enter) (1) (0) (enter) (1) (0) (enter) (stat) (-->) (enter) (enter)

What each row is:

1] Mean (average)

2] Sum (of each value)

3] Sum (of the square of each value)

4] Sample Standard Deviation (divided by n-1 when calculating)

5] Standard Deviation (divided by n when calculating)

6] Number of Items

7] Minimum (smallest value)

8] First Quartile (value at the 25% mark)

9] Median (middle value)

10] Third Quartile (value at the 75% mark)

11] Maximum (largest value)

undergo in ideas the formulation, z = (x(bar) - x)/s x(bar) = ninety 8.2 s = .sixty two z = 2.3 2.3 = (ninety 8.2 - x)/.sixty two .sixty two(2.3) = ninety 8.2 - x a million.426 - ninety 8.2 = ninety 8.2 - x - ninety 8.2 -x = -ninety six.774 x = ninety six.774 So Sally's temp. is ninety six.seventy 8 ranges Fahrenheit. i'm uncertain if there's a particular application on a TI-80 3, I incredibly have a TI-80 4, and that i'm nonetheless uncertain. you're able to be able to desire to graph it via putting y = (ninety 8.2 - x)/.sixty two and scroll down around the place y is approximately equivalent to 2.3, inspite of the undeniable fact that it incredibly isn't any longer precise simply by fact at x = ninety six, y = 3.5484 and at x = ninety seven, y = a million.9355 and 2.3 is someplace in there, yet so some distance as a application, i'm no longer fairly specific.