Write the equation of a line that passes through the points (7,-8) and (-1,8)?

Calculate the slope by --> (y2 - y1) / (x2 - x1)

slope = (8-[-8]) / (-1 - 7) = -2

Use the formula 'y = mx +c'

Use either of the 'x' or 'y' values given.

8 = -2(-1) + c ---> c = 6

y = -2x + 6

the hassle-free line equation is y = mx +c basically placed the factor fairly than x&y and you get c i'm doing one for you:- (-3,4) and slope 2 placed x=-3, y=4 and m=2 interior the equation y=mx+c it is 4= 2*-3 + c or 4 = -6 + c or c=4+6 or c=10 subsequently the equation is y=2x + 10 that's equated with y – 4 = 2(x + 3) because of the fact y-4 = 2(x+3) y-4 = 2x + 6 or y= 2x + 10 attempt something interior the comparable way. this could polish your psychological skills. do no longer count on exterior components. Do it your self.

P(7, - 8 ) and Q ( - 1, 8 )

vector (QP) = ( 8, - 16)

8x - 16y + C = 0

8( - 1 ) - 16( 8 ) + C = 0

- 8 - 128 + C = 0

- 136 + C = 0

C = 136

8x - 16y + 136 = 0

x - 2y + 22 = 0

Use (y2 -- y1) / (x2 -- x2)