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Algebra II! HELP with equation!?
Solve: Simplify the radical answers and round three decimal places:
1) -2|7x| ≥ 46
2) 3x^2 + 5 = 65
3) -2(x+7)^2 = -34
4) x^2 + 15x + 50 = 0
5) x^2 - 4x + 1 = 20 -7
6) 3x^2 + 5x + 2 = 0
1 Answer
- davidLv 78 years agoFavorite Answer
-2|7x| ≥ 46
Divide both sides by -2 (remember to flip the sign when dividing by a negative)
|7x| ≤ -23
7x ≤ -23 or -7x ≤ -23
x ≤ -23/7 or x ≥ 23/7
3x^2 + 5 = 65
3x^2 = 60
x^2 = 20
x = ±√20
-2(x+7)^2 = -34
(x+7)^2 = 17
x+7 = ±√17
x = -7 ± √17
x^2 + 15x + 50 = 0
(x+10)(x+5) = 0
x = -10 or x = -5
x^2 - 4x + 1 = 20 -7
x^2 - 4x + 1 = 13
x^2 - 4x -12 = 0
(x+2)(x-6) = 0
x = -2 or x = 6
3x^2 + 5x + 2 = 0
For this one I'd use the quadratic formula. x = [-b ± (b^2 - 4ac)] / 2a
x = [-5 ± (5^2 - 4(3)(2))] / 2(3)
x = [-5 ± (24 - 24)] / 6
x = (-5 ± 1) / 6
x = -1 or x = -2/3