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Algebra II Equation?? 10 Points! HELP!?
Solve: Simplify the radical answers and round three decimal places:
1) x^3 - 3x - 16x - 12 = 0
2) x^2 + 7x^2 + 6x = 0
3) x^3/4 - 8 = 19
4) (3x+10)^1/3 = -5
5) 2 (cube root 4√ x-11) = 6
2 Answers
- Julius NLv 78 years agoFavorite Answer
1) (x^3 - 3x - 16x - 12 )/(x+4)= ( x^2 -4x -3)
x^2 -4x -3=0
x^2 -4x = 3
x^2 -4x -3 = 0; Quadratic equation: x = -0.6458 & x = 4.6458
2) x^2 + 7x^2 + 6x = 0
x^2 +7x^2 +6x = 0
8x^2 +6x = 0
8x^2 +6x = 0
8x^2 +6x = 0; Quadratic equation: x = -3/4 & x = 0
- petrovichLv 44 years ago
All 3 issues require a similar steps. a million. -5(-6 - x) = 6 + 3(8+2x) Distribute 30 + 5x = 6 + 24 + 6x combine like words 30 + 5x = 30 + 6x assemble variable words on the left 30 - 1x = 30 Subtract 30 from each and every side -1x = 0 Divide each and every side by technique of -a million x = 0 2. -6(7 -x )=10(x+3) - 24 Distribute -40 2 + 6x = 10x + 30 -24 Like words -40 2 + 6x = 10x + 6 assemble variables -40 2 - 4x = 6 upload 40 2 -4x = 40 8 Divide by technique of -4 x = -12 3. -3(-4x + 5) = 5(-3x + 7) + 10 12x - 15 = -15x + 35 + 10 12x - 15 = -15x + 40 5 27x - 15 = 40 5 27x = 60 x = 60/27 = 20/9
