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What volume of 0.151 M Li2S solution is required to completely react with 162 mL of 0.151 M Co(NO3)2?
Consider the reaction:
Li2S(aq) + Co(NO3)2(aq) ---> 2 LiNO3(aq) + CoS(s)
What volume of 0.151 M Li2S solution is required to completely react with 162 mL of 0.151 M Co(NO3)2?
1 Answer
- Lexi RLv 78 years agoFavorite Answer
The solutions are the same concentration and the reagents react in a 1:1 ratio (from the equation) so you will need an equal volume, 162 ml of 0.151 M Li2S.
But here are the calculations....
moles Co(NO3)2 = molarity x litres
= 0.151 M x 0.162 L
= 0.024462 mol
1 mole Li2S reacts completely with 1 mole Co(NO3)2
So moles Li2S needed = moles Co(NO3)2
= 0.024462 mol
Molarity = moles / Litres
therefore
Litres Li2S = moles / molarity
= 0.024462 mol / 0.151 M
= 0.162 L
= 162 ml
