how many gallons of water would a 151/2' wide, 31' long, and 31/2' deep pool hold?

Determining volume is a 7th grade math problem. All you do is multiply the length x the width x the depth and that gives you cubic units (the units here are feet).

So, 15.5 x 31 x 3.5 = 1681.75 cubic feet.

THEN, I used the internet (google) to find out how many gallons of water there are in ONE cu. ft. of water and I found that there are 7.48052 gallons in one cubic foot. So, I multiplied 1681.75 x 7.48052 and found that there are 12,580.36364 gallons in the pool.

That relies upon on all of its dimensions. in case you recommend that it somewhat is a around pool, 20 feet throughout the time of and four feet down, then the quantity of the pool is: Pi * 10ft ^2 * 4ft = 4 hundred Pi cubic feet of water ~= 1257 feet^3 Now a million cubic foot ~= 7.40 8 gallons, so we've 1257 feet^3 * 7.40 8 gal / a million feet^3 ~= 9400 gallons