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Zaphod
Zaphod asked in Education & ReferenceHomework Help · 8 years ago

What is the range of this function?

f(x) = (3x+2)^3 - 5, for x>=0

2 Answers

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  • Geronimo
    Lv 7
    8 years ago
    Favorite Answer

      f(x) = (3x + 2)³ – 5  ...  for:   x  ≥  0

    f(x) has no discontinuities.

    f(x) increases as "x" increases, so the minimum f(x) value is at:   x  =  0

    where:   f{0}  =  3

    ... so the range is:  3   ≤   f(x)   <   ∞

    ... for the domain:  0   ≤   x �� <   ∞

  • Paladin
    Lv 7
    8 years ago

    evaluate the function for x=0 and you will see the smallest the outcome can be

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