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why does THF only function as a weak ligand for low oxidation state metals?

Whereas CO can recieve pi backdonation THF lone pairs are only available through sigma bonding.I think its something to do with the shape through group theory..

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  • ?
    Lv 7
    8 years ago
    Favorite Answer

    There are no AOs of a suitable energy (and symmetry) on the O atom of THF to accept π electron density from the filled metal d AOs. Indeed, you could argue that there would a repulsive interaction between the unbound lp on O and the filled d AOs on the metal. As it is O is hard and there is a poor H*OMO-LUMO match and the σ bond. M(0) is of course soft. So in the very useful Cr(CO)5(THF) the THF readily dissociates to form on addition of L Cr(CO)5L where L is soft ligand (PR3, π acceptor ligand).

    M(III) -THF cmplxs are more stable.

  • Anonymous
    4 years ago

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