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safasmets
safasmets asked in Science & MathematicsChemistry · 8 years ago

what is the normal boiling point of a solution prepared by dissolving 12.7g KNO3 in 20.2 g water?

Kb of water is 0.51

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  • EM
    Lv 7
    8 years ago
    Favorite Answer

    (12.7 g)(mol / 101.1 g) = 0.1256 mol

    ∆Tb = i(Kb)m

    ∆Tb = 2(0.51°C/m)(0.1256 mol / 0.0202 kg)

    ∆Tb = +6.3°C

    Tb = 106.3°C

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