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¿derivada trigonometrica urgente por favor?
Csc3x^2 ctg 3x^2 dx / csc^4 3x^2
por favor ayuda urgente!!!! gracias
1 Answer
- Anonymous8 years agoFavorite Answer
si la funcion es f(x)=(Csc3x^2) (ctg 3x^2) / (csc^4 3x^2) (porque dx no se que hace ahi solo deberia esta si quieres integrar)
entonces simplificando
f(x)=(ctg 3x^2) / (csc^3 3x^2) llevandolo a sen y cos
f(x)=(cos3x^2/sen3x^2)/(1/sen^3 3x^2) simplificando
f(x)=(cos3x^2)(sen^2 3x^2) ahora derivando
d(f(x))/d(x)= -(sen3x^2)(6x)(sen^2 3x^2)+(cos3x^2)2(sen 3x^2)(cos 3x^2)(6x)
ordenandolo
f'(x)=6x(sen3x^2)(-sen^2 3x^2+cos^2 3x^2)
espero no haberme ayudado y no haberme equivocado