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If a wire of resistance R & length L is used to form another wire of length 2L without changing its volume,?
what is the resistance of the new wire?
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- CwCcLv 78 years agoFavorite Answer
R = p L/A
V = LA = (2L)(A/2)
If the length is doubled while the volume is held constant, the cross sectional area must fall by half.
R' = p (2L)/(A/2) = 4p L/A = 4R
The resistance quadruples.
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