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solubility of Sb2S5 is x mol/dm^3 at 25 degree celcious, What is the solubility product of Sb2S5?
how do you work this out? ( with all the steps)
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- ?Lv 78 years agoFavorite Answer
Sb2S5 (s) <-------> 2Sb5+ (aq) + 5S2- (aq)
[Sb2+] = 2x mol/dm^3
[S2-] = 5x moe/dm^3
so Ksp = [Sb2+]^2 [S2-]^5 = [2x]^2 [5x]^5 = 4x^2 X 3125x^5 = 12500x^7
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