how to expand and simplify algebraic expressions?

SO we have :

6-2(n+4)

we will factor in the negative two into the parenthesis giving us a negative two 'n' and a negative eight:

6-2n-8

Now we combine like terms. Since there is only one negative two 'n' then it stays the same. However, since negative eight and six are the like terms, then we will combine them to give us negative two

-2n-2

when there's terms in parentheses, what your doing is multiplying those terms( separated by a + or -) by the term outside.

In this example your multiplying (n+4) by -2. You can consider it being written as 6 + negative 2. . . etc. It's important to remember the negative sign : )

6-2(n+4)

6 - 2*n + (-2)* (4)

6 - 2n -8

-2n - 2

To keep in mind when your multiplying 2 groups you multiply using the FOIL method (First Outside Inside Last)

So just to change your expression a little:

(6-2) (n+4)

(First) 6n + (Outside) 24 (Inside) -2n (Last) -8

6n + 24 -2n -8

4n +16

I hope that helps : )

OK, First of all, be cool and read everything calmly.

Your question is 6-2(n+4)

according to BODMAS (brackets, OF, division, multiplication, addition and subtraction)

Do this:

6-2(n+4)=6-{-2(n+4)} Categorizing...

=6-{-2n-8} Solved bracket first, i.e. multiplied -2 with n as well as 4

=6+2n+8 Solved the last step! multiply 6 with everything inside the braces!

=2n+14

Your done!

All the best for your test!

Using PEMDAS

6 - 2(n+4) Top priority is of Parenthesis

6 - 2*n - 2*4 = 6 - 2n - 8

-2n - 2 or you may write as -2(n+1)

look and try to understand

6-2(n+4 )

6-2n-8 ( I did this because the -2 is stick to the ( ) so you multiplie it to everything that is inside

2n-6-8 ( now that there is only one "n" you put it away and you resolve what is similar )

2n-2 ( because 6-8 makes -2 )

Wait, I didn't know they taught Algebra at Hogwartz!

-2n+10

(2x + 5) (3x - 4 )