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i am new to c++ program and i new to make a program.?
a program that asks the user to enter an integer between 0 and 63, and then prints the number in octal (base The program should have the following :
Enter a number between 0 and 63: 28
The number in octal (base 8) is: 34
i know If n is an integer, then n%8 is the last digit of the octal number and n/8 is the first digit.
1 Answer
- daSVgrouchLv 78 years agoFavorite Answer
int numIn;
int [] digits = new int(9);
cout >> "Enter a number between 0 and 63";
cin >> numIn;
int i = 0;
while (numin > 0 ) {
digits[i++] = numin%8;
numin /= 8;
}
