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Help me in phyics! How should i solve this?
A gas thermometer registers an absolute pressure corresponding to 325 mm of mercury when in contact with water at the triple point. What pressure does it read when in contact with water at the normal boiling point?
1 Answer
- AnthonyLv 78 years agoFavorite Answer
P1V1/T1 = P2V2/T2
V1 = V2 = Volume of thermometer = V
P1 = 325
P2 = P2
T1 = 273.16 K
T2 = 373.15K
325*V/273.16 = P2V/373.15
373.15*325/273.16 = P2
444 mm of mercury absolute = P2 = Answer (to 3 sig figs)
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