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Calorimetry question help?
Before you go onto the Internet ad lookup the specific heat capacity of the next solutions. Try to solve it without that information and only use what's presented.
This is the only question I was assigned to do which clearly stumped me:
A student missed 100ml of 1.50mol/l sulfuric acid with 200ml of 1.5mol/l sodium hydroxide. Both solutions were at 19.06'c and the highest temp was 34.06'c. Calculate the molar enthalpy of neutralization for sulfuric acid.
1 Answer
- 8 years agoFavorite Answer
Change in temperature = highest temp - initial temp
mass of solution = 100+200 = 300 g (assume that density of solution = 1g/cm3)
specific heat capacity of water = 4.14 J/K/g
==> Calculate the heat released from neutralisation
Multiply the concentration and volume to find the amount of acid and NaOH.
Identify the limiting reagent, and use that to find the amount of water produced during neutralisation.
Finally, molar enthalpy of neutralisation = - heat released / amount of water produced
All the best.
