How do I calculate the osmotic pressure of 0.2 mole solution of CACL2?

CaCl2 : 3 molecules

P = 3*0,2 = 0,6

You can consider CaCl2 to be soluble in water. It therefore produces 3 ions in the equation below (n=3)

alpha is just how soluble in water. We will say it is very soluble

The van t'Hoff factor is i = 1 + (n-1)*alpha

i = 1 + (3 - 1)

i = 3

The osmotic pressure formula is

P = i * M * R * T

P = ???

i = 3 from above

M = 0.2 mol

R = 0.08206 L atm/oK

we need a temperature to do this. We'll suppose it is a standard temperature of 273 oK in 1 liter

P = 3 * 0.2mol * 0.08206 * 273

P = 13 which seems awfully high.but that's what it comes to.