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given:sin2x=(√15)/8 determine cosx?
given:sin2x=(√15)/8 determine cosx. plz explain the procedure aswell
Update:
btw x E [45;90]
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- AlekoLv 68 years ago
from the basic trig equation sin(2x)= sqrt(1-cos^2(2x))
so sqrt(1-cos^2(2x)=sqrt(15)/8 square both sides to get :
1-cos^2(2x)=15/64 cos^2(2x)= 49/64 and cos^2(2x)=7/8
but cos^2(2x)=cos^2x-sin^2x so 2cos^2x=7/8+1
cos^2x=15/16 and cosx=sqrt(15)/4
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