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How do I solve this thermochemistry problem?
A systems volume shrinks by decreasing 9.60 L under constant pressure of 1.50 atm while absorbing 1.108 kJ of heat energy?
Determine the sign and numerical value of internal energy, work and enthalpy in J or kJ.
I am able to figure out work but I am struggling to find the internal energy and enthalpy. Thanks for the help.
1 Answer
- 8 years agoFavorite Answer
ΔU = Q+W
(or there might minus sign in the first equation above (Q - W) depending if the definition used is for work done by the system or on it. Anyway in this case
ΔU = Q - PΔV
as for the second part
ΔH = ΔH +ΔPV
here
ΔH = ΔU +PΔV = Q