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HELP with 2 math questions please!!!!!!?
Find the constant of variation for the relation in questions 1-2, and use it to write an equation for the statement. Then solve the equation.
1. If y varies inversely as the square of x, and y=1/2 when x=1, find y when x=9.
2. if y varies directly as x and z, and y=6 when x=9 and z=3, find y when x=7 and z=2.
1 Answer
- 8 years agoFavorite Answer
1) y (is proportional to) 1/(x^2)
y= k/x^2
let y=0.5, x=1
0.5 = k/1
k=0.5
let x=9
y=(0.5)/9^2
y=0.5/81 = 1/162
y (is proportional to) xz
y=kxz
6 = 27k
k=2/9
let x=7, z=2
y= (2/9)*14
y=28/9
OR
y= k(x+z)
let y=6, x=9, z=3
6=12k
k=0.5
let x=7, z=2
y=0.5*14
y=7
I'm not too sure which one you want, but i'm guessing the second. the question isn't very clear
