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Suppose some of the zeros of f(x)=0 are 2,-5 and 1/2?
Please help me with this I am so lost.
Suppose some of the zeros of f(x)=0 are 2,-5 and 1/2, find the following.
Explain how you found the answers.
a. f(x-2)=0 b. f(x+6)=0 c. f(3x)=0 d.f(-1/4x)=0
2 Answers
- Anonymous8 years agoFavorite Answer
Since some of the zeros of f (x)=0 are 2,-5, 1/2
f (x)=(x-2)(x+5)(2x-1) Q (x), where Q (x) is some function in terms of x.
a) So the zeros of (x-2-2)(x-2+5)(2(x-2)-1) Q (x-2)=f (x-2)=0 has 4, -3, 5/2 as some of the zeros.
The rest r similar.
- DanishLv 58 years ago
is it zeros of f(x) are 2,-5,1/2 not some of zero
then
f(x)=(x-2)(x+5)(x-1/2)
a . replace x by (x-2)
f(x-2)=(x-2-2)(x-2+5)(x-2-1/2)
=(x-4)(x+3)(x-5/2)
=(x^2-x-12)(2x-2)/2
=1/2(2x^3-7x^2-19x+60)
similarly do b,c,d parts
