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? asked in Science & MathematicsChemistry · 8 years ago

Molarity of a solution by mixing 75 ml of 3 M Nh4OH with enough water to give 250 ml of solution?

Chemistry, shows all steps thanks

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  • Nikhilesh
    Lv 7
    8 years ago
    Favorite Answer

    Answer

    3 M NH4OH solution is 3 moles of NH4OH / 1000 ml of the solution

    75 ml of this soln = 3*75/1000 moles of NH4OH , that is 0.225 moles of NH4OH

    If this 75 ml soln is made up to 250 ml , molarity will be 0.225 / 0.25 = 0.9 M

  • BB
    Lv 7
    8 years ago

    1000 mL of 3M NH4OH contains 3 moles so 75 mL contains 75/1000 * 3 moles

    = 0.225 moles. Molarity = mol/L = 0.225 mol / 0.250 L = 0.9 M.

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