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A compression, at a constant pressure of 50 kPa, is performed on 4 moles of an ideal monatomic gas (Cv = 3/2..?
A compression, at a constant pressure of 50 kPa, is performed on 4 moles of an ideal monatomic gas (Cv = 3/2 R). The compression reduces the volume of the gas from 0.25 m3 to 0.12 m3. The work done by the gas, in kJ, is closest to?
What is Cv? I have no idea where to start.. I feel like this was the day I missed in physics
1 Answer
- donpatLv 78 years agoFavorite Answer
Hello antran007....
----------------------------------------------------
WB = Integral [ P dV ]
Since P is constant,
WB = ( P ) ( V2 - V1 )
WB = ( 50 kPa ) ( 0.12 - 0.25 cu m ) = - 6.5 kJ <-----------------------------------
CV = ( 3 / 2 ) ( R )
CV = ( 3 / 2 ) ( 8.314 J / gmol - K deg ) = 12.47 J / gmol - K deg
Also :
CV = 12.47 kJ / kgmol - K deg <-------------------------------------------
CP = CV + R
CP = ( 3/2 + 1 ) ( R ) = ( 5 / 2 ) ( R )
Delta U = ( n ) ( CV ) ( T2 - T1 )
Delta H = ( n ) ( CP ) ( T2 - T1 )
CV = du/dt with constant volume
CP = dh/dt with constant pressure
