Is it possible to factor this problem?

It's usually above the 6...So shift and 6 keys together

Consider the product of the x^2 coefficient and the constant

8 * 14 = 112

look at the factors of 112

8 and 14, but their sum is 22

4 and 28, but sum is 32

2 and 56, their sum is 58

7 and 16, their sum is 23 --- this is the one we're looking for!

Sum, because 8 is +8, and a positive times a positive is positive and negative times a negative is a positive. If the sign of the constant was a negative, we'd loom at the difference.

and because the coefficient in from of the x factor is negative, they both have to be negative (ie -7 and -16)

so: 14x^2 -7x -16x + 8

==> 7x((2x -1) - 8(2x -1)

==> (2x-1)(7x -8)

Multiply out ==> 14x^2 -16x -7x + 8 = 14x^2 - 23x + 8 which is what we started with.

14x^2-23x+8 = 14x^2-16x - 7x+8

= 2x(7x-8) -1(7x - 8) = (2x-1)(7x-8)